I can check my board and the app will tell where i have made mistakes and let me back up, so I know when I have made a mistake. I find that I can use singles chains when I have exhausted easier strategies. I recently found they are also called Windoku. I am trying to get through a series on fiendish Hyper-Sudoku puzzles (from an Android app - Super Sudoku). by: Can I use singles chains in Windoku puzzles? This would reflect the full meaning of Rule 2 and not just half of it as now. This needs to be enhanced with "and all blue coloured candidates become solutions". The fundamental problem is in the thinking - the message in the results window says "all yellow coloured candidates can be removed". its membership of the chain is forgotten and its fate is decided by later scanning. But the 5 in E9 becomes a Hidden Single and doesn't get promoted to a solution until two steps later, i.e. Six of them become Naked Singles and become solutions in the next step because they are singles. In the example for Rule 2 there are seven ON candidates. The beauty of Simple Colouring Rule 2 is that we know immediately the fate of every candidate in the chain. I'm sure that you know what you mean and not what you say in your reply to my comment of 2 March - you're not going to "remove all candidates on the ON cells" are you? What I would like to see is all ON candidates become solutions either in the same or the next step of the solver. Thanks for the challenging and interesting site. In which case the strategy of 'Simple Colouring/Singles Chains' becomes entirely redundant.įrom the humanities side, I would point out that the apostrophe in "Single's" isn't needed, you're trying to mark plurality not possession. Having noted this, even greater simplification of strategies can be achieved by noting that all instances of Rule 4 Singles Chains are in fact examples of X-cycles with an odd number of nodes - the candidate that sees both ends of a chain that begins and ends on strong links will be the odd one out, linked by a W-W connection. 'off chain' distinction, which is perhaps more confusing than enlightening? If this is the case, then Rule 2 is redundant, and there would be no need for the 'off-chain' vs. (But I can't provide a mathetmatical proof). I'm pretty sure that any eliminations found by applying Rule 2 can also be found by applying Rule 4, simply by starting at different points and following different paths through the network of connections.
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